I read a comment the other day somewhere (I think underneath a media article or something) that was given by some guy who'd been out in the west desert last year. He was out there with some buddies and they came across a huge gaping hole in the ground (vertical mine shaft)...no blocks, doors, signs, grates, or anything. It was just there. He said it was about 10' x 10' across. They poured gasoline in an empty milk jug, stuck a rag in it, lit it, and dropped the thing. It was an entire minute before they saw it hit bottom.
(b&ubm)
I believe the adventurers were exaggerating the long time period,
(a full minute) it took for the milk jug to hit the bottom of the hole --
OR the jug fell into an earthquake crevasse.
IMO, IF the flaming jug took an
entire minute to reach the bottom, it certainly did not fall into a primitive man-made mine shaft.
My college basic physics is pretty rusty, but here's what I remember:
The general gravitational speed of free-fall is 32 feet per second, with no resistance.
During each second of fall the instantaneous speed of the object increases by an additional approximate 32' per second. This gain in speed per second is the
acceleration.
The formula for finding the distance an object would fall is:
Distance = 1/2 (x) Gravitational speed (x) time/squared
The following shows the basic math steps to determine the distance to the bottom of the hole when one minute is the time from top to bottom.
Distance = 1/2 (x) 32' per sec (x) 60 seconds/squared
Distance = 1/2 (x) 32 (x) 3,600
Distance = 1/2 (x) 115,200
Distance to the bottom of the hole = 57,600 feet or 10.9 MILES
I doubt if the posters could have seen the flaming milk jug hit the bottom of the hole if the jug traveled 10 miles into the Earth. I doubt if they would have seen it if the jug traveled even
ONE mile to the bottom.
moo